16. Program to print the given pattern
// Program to print the given Pattern /* 1 2 6 3 7 10 4 8 11 13 5 9 12 14 15 ... till n rows */ /* For example : For n=3 1 2 4 3 5 6 For n=6 1 2 7 3 8 12 4 9 13 16 5 10 14 17 19 6 11 15 18 20 21 */ #include <stdio.h> #include<conio.h> // Linux user - Remove this int main() { // Declaring variable i, j to iterate loop int i, j; // Declaring variable n = maximum rows int n; //Declaring variable k and num to help in generating "values" int k, num=1; // Inputting Number of rows printf("Enter number of rows : "); scanf("%d",&n); // Running loop for rows for (i=1; i<=n ; i++) { num=i; k=n-1; // printing values for (j=1; j<=i; j++) { // %-4d = reserves 4 spaces for printing "value" to obtain clarity in pattern printf("%-4d",num); num=num+k; k=k-1; } printf("\n"); } getch(); // Linux user - Remove this return 0; }
17. Program to print the given pattern
// Program to print pattern : Hollow Diamond /* ******** ******** ******* ******* ****** ****** ***** ***** **** **** *** *** ** ** * * * * ** ** *** *** **** **** ***** ***** ****** ****** ******* ******* ******** ******** LOGIC : BREAKING IT UP : It has 2 parts First part : ******** ******** ******* ******* ****** ****** ***** ***** **** **** *** *** ** ** * * Which is further divided into : First Sub Part : ******** ******* ****** ***** **** *** ** * Second Sub part : ******** ******* ****** ***** **** *** ** * And ofcourse the spaces before it. Second Part : * * ** ** *** *** **** **** ***** ***** ****** ****** ******* ******* ******** ******** Which is further divided into : First Sub Part : * ** *** **** ***** ****** ******* ******** Second Sub Part : * ** *** **** ***** ****** ******* ******** And the spaces before it. */ #include<stdio.h> #include<conio.h> // Linux user - Remove this int main() { // Declaring variable i, j, s to iterate loop int i, j, s; // Declaring ms = maximum space int ms = 1; // Running loop for rows for first part for(i=1;i<=8;i++) { // Printing first Sub Part : for(j=8;j>=i;j--) { printf("*"); } // Printing spaces for(s=1;s<=ms;s++) { printf(" "); } // Incresing spaces ms=ms+2; // Printing Second Sub Part : for(j=8;j>=i;j--) { printf("*"); } printf("\n"); } printf("\n"); // Initialising ms = 15 i.e the maximum space ms = 15; // Running loop for Second Part for(i=1;i<=8;i++) { // Printing first Sub Part : for(j=1;j<=i;j++) { printf("*"); } // Printing spaces for(s=1;s<=ms;s++) { printf(" "); } // Reducing spaces ms=ms-2; // Printing Second Sub Part : for(j=1;j<=i;j++) { printf("*"); } printf("\n"); } getch(); // Linux user - Remove this return 0; }
18. Program to print the given pattern
/* * *** ***** ******* ********* ******* ***** *** * BREAKING IT UP : The above pattern has two parts First Part : * *** ***** ******* ********* Second Part : ******* ***** *** * */ #include<stdio.h> #include<conio.h> // Linux user - Remove this int main() { // Declaring variable i, j, s to iterate loop int i,j,s; // Declaring variable ms = maximum space int ms = 5; // Declaring variable to print "*" ( asterik ) int as = 1; // Running loop for First part for(i=1;i<=5;i++) { // Printing Space for(s=1;s<=ms;s++) { printf(" "); } // Reducing spaces ms--; // Printing First Part for(j=1;j<=as;j++) { printf("*"); } // Increasing Asterik ( "*" ) as=as+2; printf("\n"); } // Re-initialising ms = maximum space and aterik ms=2; as=7; // Running loop for Second Part for(i=1;i<=5;i++) { // Printing Space for(s=1;s<=ms;s++) { printf(" "); } // Increasing spaces ms++; // Printing First Part for(j=1;j<=as;j++) { printf("*"); } // Decreasing Asterik ( "*" ) as=as-2; printf("\n"); } getch(); // Linux user - Remove this return 0; }
19. Program to print the given pattern
/*
8 4 2 1
4 2 1
2 1
1
*/
#include<stdio.h>
#include<conio.h>
int main()
{
int n=8,m;
int i,j;
m=n;
for(i=4;i>=1;i--)
{
for(j=1;j<=i;j++)
{
printf("%d ",m);
m=m/2;
}
m=n/2;
n=n/2;
printf("\n");
}
getch();
return 0;
}
20. Program to print the given pattern
#include<stdio.h> #include<conio.h> // Linux user - Remove this int main() { int arr[30],temp[30],i,j,k,l,n; printf("Enter the number of lines to be printed: "); scanf("%d",&n); temp[0]=1; arr[0]=1; for(j=0;j<n;j++) printf(" "); printf(" 1\n"); for(i=1;i<n;i++) { for(j=0;j<n-i;j++) printf(" "); for(k=1;k<i;k++) { arr[k]=temp[k-1]+temp[k]; } arr[i]=1; for(l=0;l<=i;l++) { printf("%2d",arr[l]); temp[l]=arr[l]; } printf("\n"); } getch(); // Linux user - Remove this return 0; }
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